You've got 100 numbers between 1 and 100.
50 of them are even, so they're divisible by 2. Now, you have 100 divided by 3 = 33 + 1 remainder. This means that there are
33 numbers from 1 to 100 divisible by 3, but you have to pick only the odd ones, since you;ve already eliminated the even ones.Feb 2, 2009
read more >>