As a physicist, I can tell you that the distance you fall in a vacuum, assuming no air resistance, can be calculated using the equations of motion for an object in free fall. The formula to calculate the distance \( d \) fallen in time \( t \) is given by:

\[ d = \frac{1}{2} g t^2 \]

where \( g \) is the acceleration due to gravity, which is approximately \( 9.81 \, \text{m/s}^2 \) on the surface of the Earth.

For a fall of 3 seconds, the distance \( d \) would be:

\[ d = \frac{1}{2} \times 9.81 \, \text{m/s}^2 \times (3 \, \text{s})^2 \]
\[ d = \frac{1}{2} \times 9.81 \times 9 \, \text{m} \]
\[ d = 4.905 \times 9 \, \text{m} \]
\[ d = 44.145 \, \text{m} \]

So, you would fall approximately 44.145 meters in 3 seconds.

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The first equation shows that, after one second, an object will have fallen a distance of 1/2 �� 9.8 �� 12 = 4.9 meters. After two seconds it will have fallen 1/2 �� 9.8 �� 22 = 19.6 meters; and so on.read more >>